Question 31

The first term of a series is unity. Every even term is thrice the term preceding it and every odd term is seven times the term preceding it. The sum of the first hundred terms is

Solution

The series is 1, 3*1, 7*3*1, 3*7*3*1, 7*3*7*3*1, 3*7*3*7*3*1.........100 terms

The series of the even terms = 3*1, 3*7*3*1, 3*7*3*7*3*1.....

Sum of the first 50 even terms = $$\frac{3(21^{50}-1)}{20}$$

The series of the odd terms = 1, 7*3*1, 7*3*7*3*1.....

Sum of the first 50 even terms = $$\frac{1(21^{50}-1)}{20}$$

Required sum =  $$\frac{3(21^{50}-1)}{20}$$+$$\frac{1(21^{50}-1)}{20}$$

=4*$$\frac{21^{50}-1}{20}$$

=$$\frac{1}{5}(21^{50} - 1)$$

A is the correct answer.


Create a FREE account and get:

  • All Quant Formulas and shortcuts PDF
  • 40+ previous papers with solutions PDF
  • Top 500 MBA exam Solved Questions for Free

cracku

Boost your Prep!

Download App