Question 36

If tanθ + cotθ = 5, then the value of $$tan^2θ + cot^2θ$$ is

Solution

Given : tanθ + cotθ = 5

Squaring both sides

=> $$(tan\theta+cot\theta)^2=(5)^2$$

=> $$tan^2\theta+cot^2\theta+2(tan\theta)(cot\theta)=25$$

=> $$tan^2\theta+cot^2\theta=25-2=23$$

=> Ans - (C)

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