Let $$\angle\ HBG$$ = 2y
$$\angle\ BAF$$ = 2y (corresponding angles are equal)
$$\angle\ FAC\ =\ \angle\ CAB$$ = y
$$\angle\ ABG$$ = 180 - 2y
$$\angle\ ABC\ =\ \angle\ CBG$$ = 90 - y
Sum of all angles of a triangle =Â $$180^{\circ\ }$$
In traingle, $$\angle\ CAB$$ = y, $$\angle\ ABC$$ = 90-y
y + 90 - y +Â $$\angle\ ACB$$ = 180
$$\angle\ ACB$$ =Â $$90^{\circ\ }$$
$$\angle\ ECB$$ = 180 - 90 = 90
2x = 90
x =Â $$45^{\circ\ }$$
Answer is option B
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