Given : $$sin(\theta+18^\circ)=\frac{1}{2}$$
=> $$sin(\theta+18^\circ)=sin(30^\circ)$$
=> $$\theta+18^\circ=30^\circ$$
=> $$\theta=30^\circ-18^\circ=12^\circ$$
Now, $$180^\circ=\pi$$ radians
=> $$12^\circ=\frac{\pi}{180} \times 12=\frac{\pi}{15}$$ radians
=> Ans - (B)
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