Solution
$$\because$$ Maximum Value of $$a\sin{\theta}+b\cos{\theta}=\sqrt{a^{2}+b^{2}}$$
$$\therefore$$ Maximum Value of $$2\sin{\theta}+3\cos{\theta}=\sqrt{2^{2}+3^{2}}$$
$$=\sqrt{13}$$
Hence, Correct option is B.
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