Question 4

For what value of $$y$$, if $$x^2+\frac{1}{12}x+y^2$$ is a perfect square ?

Solution

Expression = $$x^2+\frac{1}{12}x+y^2$$

= $$x^2+2(x)(\frac{1}{24})+y^2$$

Now to make it a perfect square, $$y^2$$ is replaced by $$(\frac{1}{24})^2$$

= $$(x)^2+2(x)(\frac{1}{24})+(\frac{1}{24})^2$$

=> $$y=\frac{1}{24}$$

=> Ans - (A)

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