SSC CHSL 17 March 2018 Morning Shift

Question 3

Determine the value of $$\frac{x+y}{x+2y}$$ when $$\frac{2x+y}{x+4y}=3$$

Solution

Expression : $$\frac{2x+y}{x+4y}=3$$

=> $$2x+y=3x+12y$$

=> $$3x-2x=y-12y$$

=> $$x=-11y$$

$$\therefore$$ $$\frac{x+y}{x+2y}$$

= $$\frac{-11y+y}{-11y+2y}$$

= $$\frac{-10y}{-9y}=\frac{10}{9}$$

=> Ans - (D)

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