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Question 4
If $$A = \frac{0.216 + 0.008}{0.36 + 0.04 - 0.12}$$ and $$B = \frac{0.729 - 0.027}{0.81 + 0.09 + 0.27}$$, then what is the value of $$(A^2 + B^2)^2?$$
Solution
$$A = \frac{0.216 + 0.008}{0.36 + 0.04 - 0.12}$$
$$A = \frac{0.224}{0.28}$$
=0.8
$$B = \frac{0.729 - 0.027}{0.81 + 0.09 + 0.27}$$
$$B=\frac{0.702}{1.17}$$
=0.6
 $$(A^2 + B^2)^2$$=0.36+0.64=1
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