What is the ratio of the third proportionalto 0.4 and 0.8, to the mean proportional between 13.5 and 0.24?
Third proportional = $$\frac{(0.8)^2}{0.4} =Â \frac{0.64}{0.4}$$ = 1.6$$
Mean proportional = $$\sqrt{13.5 \times 0.24} =Â \sqrt{3.24}$$ = 1.8
Ratio of the third proportional to 0.4 and 0.8, to the mean proportional between 13.5 and 0.24 = 1.6 : 1.8 = 8 :Â 9
$$\therefore$$ The correct answer is option C.
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