A, B, and C have a few chocolates among themselves. A gives to each of the other two half the number chocolatesthey already have. Similarly, B and C (in that order) gives each of the other two half the number of chocolates each of them already has. Now,ifeach of them has the same number of chocolates, what could be the minimum number of chocolates they have among themselves?

Let us assume A, B, and C have x with the at the end.

In the last round, chocolates went from C to A and B:

=> A and B will have 2x/3 chocolates and the remaining chocolates will be with C = 5x/3 [why y + y/2 = x => y = 2x/3]

Now, B gives chocolates to A and C

=> A will have 4x/9, C will have 10x/9 => B has 13x/9 chocolates

Now, A gave to B and C

=> B will have 26x/27, C will have 20x/27, A will have 7x/27

=> For this to be integer x = 27 => Total chocolates with them = 27 * 3 = 81.