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Let X and Y be two events such that $$P(X) = \frac{1}{3}, P(X \mid Y) = \frac{1}{2}$$ and $$P(Y \mid X) = \frac{2}{5}$$. Then
$$P(Y) = \frac{4}{15}$$
$$P(X' \mid Y) = \frac{1}{2}$$
$$P(X \cap Y) = \frac{1}{5}$$
$$P(X \cup Y) = \frac{2}{5}$$
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