The sides of a rectangular field are in the ratio 3 : 4 with its area as 7500 sq m. The cost of fencing the field @ 25-paise per metre is
Let sides of rectangular field be $$3x$$ and $$4x$$ m respectively.
=> Area = $$lb=7500$$
=> $$3x\times4x=7500$$
=> $$x^2=\frac{7500}{12}=625$$
=> $$x=\sqrt{625}=25$$
=> Perimeter of field = $$2(3x+4x)=14x$$
= $$14\times25=350$$ m
$$\therefore$$ Cost of fencing = $$350\times0.25=Rs.$$ $$87.50$$
=> Ans - (A)
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