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Instructions
Answer the questions based on the following information. The following operations are defined for real numbers.
a # b=a + b, if a and b both are positive else a # b=1
a $$\triangledown$$ b=$$(a \times b)^{a+b}$$ if $$a\times\ b$$ is positive else a $$\triangledown$$b=1.
Question 48
$$\frac{((1\#1) \# 2) - (10^{1.3} \triangledown \log_{10}{0.1})}{1 \triangledown 2}$$
Solution
$$((1\#1) \# 2) = 2 \# 2 = 4$$
$$\log_{10} 0.1$$ = $$\log_{10} 10^{-1}$$ = -1
As $$(10^{1.3} \times -1)$$ is not positive, $$(10^{1.3} \triangledown \log_{10}{0.1})$$ = 1
$$1 \triangledown 2$$ = $$(1x2)^{(1+2)}$$ = $$2^3$$ = 8
Hence, the fraction is (4-1)/8 = 3/8
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