Question 48

The letters P, Q, R, S, and T each stands for one of 1, 2, 3, 4, and 5 but not necessarily in that order. P is odd, Q is neither 4 nor 5, R is 1, S is either 4 or 5, T is neither 2, 3 nor 4. The correct order of the digits (according to the correct order of the English alphabet) is:-

Solution

Given that P,Q,R,S and T are among 1,2,3,4 and 5. Upon tabulating the above given information we get the following table

Since it is given that R has to be 1, T has to be 5 which implies S = 4. Since 3 is the only odd number left P=3 which leaves Q=2

Hence P,Q,R,S,T = 3,2,1,4,5

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