Shyam's house, his office and his gym are all equidistant from each other. The distance between any 2 of them is 4 km. Shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office. He then reverses direction and walks till he reaches a point directly south of his office. The total distance walked by Shyam is
The house , the gym and the office forms an equilateral triangle with each side = 4Km.
Now The path covered by shyam will be :Â
The distance covered will be 4+4+4 = 12km
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