Question 5

Calculate the angle BAC if the angle BIC = $$125^\circ$$ and 'I' be the in-center of the triangle?

Solution

Given : $$\angle$$ BIC = $$125^\circ$$ and I is the incentre of the triangle

To find : $$\angle$$ BAC

Solution : Incentre of a triangle = $$90^\circ+\frac{1}{2}\times$$ (angle opposite to it)

=> $$125^\circ=90^\circ+\frac{\angle A}{2}$$

=> $$\frac{\angle A}{2}=125^\circ-90^\circ=35^\circ$$

=> $$\angle A=2\times35^\circ=70^\circ$$

=> Ans - (C)

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