Question 5

If DE is parallel to BC and bisects the other two sides of the triangle ABC such that the ratio $$\frac{AD}{DB}=\frac{5}{13}$$ and the length of the part EC is 26 cm. Then determine the length of AE (in cm).

Solution

DE is parallel to BC and let AD = 5 cm and DB = 13 cm

Also, EC = 26 cm and let AE = $$x$$ cm

=> $$\frac{AD}{DB} = \frac{AE}{EC}$$

=> $$\frac{5}{13} = \frac{(x)}{26}$$

=> $$x=\frac{5}{13}\times26=5\times2=10$$ cm

=> Ans - (B)

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