Question 5

Sum of all positive integers from 1 to 100 is:

Solution

Sum of numbers from 1 to 100 $$=\dfrac{n(n+1)}{2}$$ where n = number of terms from 1 to 100 = 100.
Therefore, Sum of numbers from 1 to 100 $$=\dfrac{100\times101}{2} = 5050$$

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IB Security 2019

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