If x ≠ -1, 2 and 5, then the simplified value of 

$$\left\{\frac{2(x^3 - 8)}{x^2 -x -2} \times \frac{x^2 + 2x +1}{x^2 - 4x - 5} \div \frac{x^2 + 2x + 4}{3x - 15}\right\}$$ is equal to:

A

$$\frac{2}{3}$$

B

$$\frac{1}{6}$$

C

6

D

$$\frac{3}{2}$$