If $$\sin A : \cos A = 4 : 7$$, then the value of $$\frac{(7 \sin A - 3 \cos A)}{(7 \sin A+ 2 \cos A)}$$ is
Let $$sin A=4$$ and $$cos A=7$$
Expression : $$\frac{(7 \sin A - 3 \cos A)}{(7 \sin A+ 2 \cos A)}$$
= $$\frac{7(4)-3(7)}{7(4)+2(7)}=\frac{28-21}{28+14}$$
= $$\frac{7}{42}=\frac{1}{6}$$
=> Ans - (D)
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