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Due to astrological reasons, a mother named all her daughters with the alphabet ‘K’ as Kamla, Kamlesh, Kriti, Kripa, Kranti and Kalpana.
i.Kamla is not the tallest while Kripa is not the most qualified.
ii.The shortest is the most qualified amongst them all.
iii.Kalpana is more qualified than Kamlesh who is more qualified than Kriti.
iv.Kamla is less qualified than Kamlesh but is taller than Kamlesh.
v.Kalpana is shorter than Kriti but taller than Kranti.
vi.Kriti is more qualified than Kamla while Kamlesh is taller than Kriti.
vii.Kripa is the least qualified amongst the daughters.
Let us arrange the daughters in the decreasing order of height first.
Kalpana is shorter than Kriti but taller than Kranti.
Therefore, Kriti > Kalpana > Kranti.
Kamlesh is taller than Kriti.
Kamlesh > Kriti > Kalpana > Kranti.
Kamla is taller than Kamlesh. Kamla is not the tallest. Therefore, Kripa must be the tallest person.
Kripa > Kamla > Kamlesh > Kriti > Kalpana > Kranti.
Let us arrange the daughters in terms of their qualification.
The shortest person is the most qualified.
Therefore, Kranti must be the most qualified person among the 6 daughters.
Kalpana is more qualified than Kamlesh who is more qualified than Kriti.
Kalpana > Kamlesh > Kriti.
Kamla is less qualified than Kamlesh. Kriti is more qualified than Kamla. Kripa is the least qualified among the daughters.
Kranti > Kalpana > Kamlesh > Kriti > Kamla > Kripa.
Height (in decreasing order):
Kripa > Kamla > Kamlesh > Kriti > Kalpana > Kranti.
Qualification (in decreasing order):
Kranti > Kalpana > Kamlesh > Kriti > Kamla > Kripa.
Kamlesh is the third tallest person. Therefore, option B is the right answer.
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