Question 58

C and D together can make a chair in 4 days and C alone can make this chair in 12 days. In how many days D alone can make this chair?

Solution

C+D = 4 days

C = 12 days

Total work = lcm(4,12)

=12

Efficiency of C+D= $$12\div4$$ =3

Efficiency of C = $$12\div12$$ =1

So ,

Efficiency of D= (Efficiency of C+D)-(Efficiency of C )

= 2

So, D can work alone = $$total work\div2$$

= 6 days

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