The number of coins collected per week by two coin-collectors A and B are in the ratio 3 : 4. If the total number of coins collected by A in 5 weeks is a multiple of 7, and the total number of coins collected by B in 3 weeks is a multiple of 24, then the minimum possible number of coins collected by A in one week is
Correct Answer: 42
Given that the number of coins collected per week by two coin-collectors, A and B, are in the ratio 3: 4
Let us assume A collects 3c coins per week and B collects 4c coins per week.
Total number of coins collected by A in 5 weeks = 5*3c = 15c, which should be multiple of 7 => c should be multiple of 7.
Total number of coins collected by B in 3 weeks = 3*4c = 12c, which should be a multiple of 24 => c should be a multiple of 2.
So, the least possible value of c is lcm(2,7) = 14.
Coins sold by A in a week = 3c = 3*14 = 42.
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