A hemispherical bowlof internal radius 9 cm, contains a liquid. This liquid is to befilled into small cylindrical bottles of diameter 3 cm and height 4 cm.Then the numberof bottles necessary to empty the bowlis

hemispherical bowl of internal radius 9 cm

r = 9 

volume of hemispherical bowl = $$\frac{2}{3} \times \pi \times r^3$$ =  $$\frac{2}{3} \times \pi \times 9^3$$ = $$486 \pi$$

small cylindrical bottles of diameter 3 cm and height 4 cm

radius = $$\frac{3}{2}$$

volume of cylindrical bottles = $$ \pi r^2 h$$

= $$ \pi \times \frac{3}{2} \times \frac{3}{2} \times  4$$ = $$9 \pi$$

no of bottles required = $$\frac{486 \pi}{9 \pi}$$ = 54