ABCD is a parallelogram in which diagonals AC and BD intersect at O. AE and DF are perpendiculars on BC at E and F, respectively. Which of the following is NOT true?
It is given that ABCD is a parallelogram, in which AC and BD are the diagonals of a parallelogram, which intersects at O.
AE and DF are perpendicular to E and F on BC.
Now in $$\triangle$$ ADC and $$\triangle$$ABD
$$\angle$$AEB=$$\angle$$DFC Â Â ---------(perpendicular always makes $$90^\circ$$)
AE = DFÂ -----------(two perpendiculars one-two parallel lines always have the same length)
AB=DCÂ -----------(opposite side of the parallelogram have the same length)
Hence $$\triangle AEB \cong \triangle DEC $$ (Side Side Angle)
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