Consider the two equiangular triangles ABC and DEF having medians as AL and DM respectively as shown in figure below.
It is given that $$\triangle$$ ABC and $$\triangle$$ DEF are equiangular triangles, thus corresponding angles are equal.
=>Â $$\triangle$$ ABC $$\sim\triangle$$ DEF
=> Ratio of perimeter = $$\frac{AB}{DE}=$$Â $$\frac{BC}{EF}=$$Â $$\frac{AC}{DF}$$Â -------------(i)
Since, AL and DM are medians, => Ratio of perimeter of $$\triangle$$ ABC to $$\triangle$$ DEF = $$\frac{AL}{DM}$$ -----------(ii)
From, equations (i) and (ii), we get :
=>Â $$\frac{BC}{EF}=\frac{AL}{DM}$$
=> Ans - (B)
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