If $$ f(x) = \log_{e}({\frac{2 - x}{9 - x^2}})$$, then the domain of the function $$f$$ is
Logarithmic function is defined only for positive values
So $${\frac{2 - x}{9 - x^2}}$$ >0 and $$9-x^{2}$$ should not equal 0.
x $$\in$$ (-3,2)$$\cup$$ (3,$$\infty$$)
D is the correct answer.
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