Question 6

In the triangle ABC, the internal bisector of angle A meets the side BC at D. If BD = 7.5 cm and BC = 9 cm. Then calculate the value of AB : AC.

Solution

Given : AD is the angle bisector of $$\angle$$ A. Also, BD = 7.5 cm and BC = 9 cm

To find : AB : AC = ?

Solution : CD = 9 - 7.5 = 1.5 cm

According to angle bisector theorem,

=> $$\frac{AB}{BD}=\frac{AC}{DC}$$

=> $$\frac{AB}{AC}=\frac{BD}{DC}$$

=> $$\frac{AB}{AC}=\frac{7.5}{1.5}=\frac{5}{1}$$

=> Ans - (C)

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