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Solution
If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency) are equal.
Thus, AP = AR and BQ = BR --------------(i)
Also, OP = OQ
=> OA + AP = OB + BQ
Substituting value from equation (i), we get :
=> OA + AR = OB + BR
=> Ans - (C)
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