Question 62

If $$\sin 5 \theta = \cos(50^\circ - 3\theta), then \theta$$ is equal to:

Solution

$$\sin5\theta=\cos(50^\circ-3\theta)$$

$$\cos\left(90^{\circ\ }-5\theta\ \right)=\cos\left(50^{\circ\ }-3\theta\ \right)$$

$$90^{\circ\ }-5\theta\ =50^{\circ\ }-3\theta\ $$

$$\theta=20^{\circ\ }\ $$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: