Question 64
A train crosses a platform 180 m long in 60 sec at a speed of 72 km/h. The time taken by the train to cross an electric pole is:
Solution
Length of platform = 180 m
Time = 60 sec
Speed = 72 km/hr = 72$$\times$$ 5/18 = 20 m/sec
Total length = length of platform + length of train = 180 + length of train
Speed = length/time
180 + length of train = 20 $$\times$$ 60
Length of train =1200 - 180 = 1020 m
The time taken by the train to cross an electric pole = 1020/20 = 51 sec
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