Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 66
For any real number x, let [x] be the largest integer less than or equal to x. If $$\sum_{n=1}^N \left[\frac{1}{5} + \frac{n}{25}\right] = 25$$ then N is
Correct Answer: 44
Solution
It is given,
$$\Sigma_{n=1}^N\ \left[\frac{1}{5}+\frac{n}{25}\right]=25$$
$$\Sigma_{n=1}^N\ \left[\frac{5+n}{25}\right]=25$$
For n = 1 to n = 19, value of function is zero.
For n = 20 to n = 44, value of function will be 1.
44 = 20 + n - 1
n = 25 which is equal to given value.
This implies N = 44
Video Solution
Create a FREE account and get:
- All Quant CAT complete Formulas and shortcuts PDF
- 35+ CAT previous year papers with video solutions PDF
- 5000+ Topic-wise Previous year CAT Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Averages QuestionsCAT Mensuration QuestionsCAT Data Sufficiency QuestionsCAT Inequalities QuestionsCAT Algebra Questions
CAT DILR Questions | LRDI Questions For CAT
CAT DI with connected data sets QuestionsCAT Routes And Networks QuestionsCAT Special Charts QuestionsCAT Data Interpretation Basics QuestionsCAT Table with Missing values Questions
