Question 67

Walking at $$\frac{3}{5}$$ of his usual speed, a person reaches his office 20 minutes late than the usual time. His usual time in minutes is:

Solution

since distance is constant. So, time is inversely proportional to speed.
ratio of the speed = 5 : 3

ratio of the time = 3 : 5

Let the usual time is $$3x$$ and delayed time is $$5x$$.

From question, time difference is 20min.

$$\Rightarrow$$ $$5x-3x$$ = 20 min

$$\Rightarrow$$ $$x=10min$$

Usual time = $$3\times10=30min$$

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