CAT 2002 QA Question

Question 7

How many numbers greater than 0 and less than a million can be formed with the digits 0, 7 and 8?

Solution

According to given condiitons, number of 1 digit nos. = 2, number of 2 digit nos. = 2*3 , number of 3 digit nos. = $$2*3^2$$ , number of 4 digit nos. = $$2*3^3$$ , number of 5 digit numbers. = $$2*3^4$$,  Number of 6 digit nos. = $$2 *3^5$$.

Total summation 2*(1+3+9+27+81+243) = 728 . 

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