If price of oranges is increased by 30%, then a person can buy 12 oranges less for Rs 208. What is the original price (in Rs) of an orange?

Let price of oranges = Rs. $$100x$$ per kg

Oranges bought for Rs. 208 = $$\frac{208}{100x}$$

New price of oranges = $$100x+(\frac{30}{100}\times100x)=Rs.$$ $$130x$$

Oranges bought for Rs. 208 = $$\frac{208}{130x}$$

According to ques,

=> $$\frac{208}{100x}-12=\frac{208}{130x}$$

=> $$\frac{208}{100x}-\frac{208}{130x}=12$$

=> $$208(\frac{1}{100x}-\frac{1}{130x})=12$$

=> $$\frac{130x-100x}{100x\times130x}=\frac{12}{208}$$

=> $$\frac{30}{13000x}=\frac{3}{52}$$

=> $$x=\frac{3}{1300}\times\frac{52}{3}$$

=> $$x=\frac{52}{1300}=\frac{1}{25}$$

$$\therefore$$ Original price = $$100\times\frac{1}{25}=Rs.$$ $$4$$

=> Ans - (B)