Question 7

If $$(x+7954\times7956)$$ be a square number, then the value of x is

Solution

$$(x+7954\times7956)$$

= [x+(7955-1)(7955+1)]

= [x+$$7955^{2}$$-1]

to become a perfect square, x-1 = 0 so x = 1.

so the answer is option A.

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