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If $$1 + \sin \theta = m\cos\theta$$, then what is the value of $$\sin \theta$$?
$$\frac{2m^{2} - 1}{m^{2} + 1}$$
$$\frac{m^{2} - 1}{m^{2} + 1}$$
$$\frac{m^{2} + 1}{2m^{2} - 1}$$
$$\frac{m^{2} + 1}{m^{2} - 1}$$
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