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A is 20% more than B. B is 25% more than C. C is how much percent less than A?
Consider C=100
Given B=25% more than C = 100 + (100 $$\times $$ 25%)
= 100 + (100 $$\times $$ 0.25)
= 100 + 25
= 125
A=20% more than B
= 150
To find C is how much percent less than A, we have C = 100 and A = 150.
Therefore, we get
=$$\frac{150-100}{150}$$
=$$\frac{50}{150}$$
= $$\frac {1}{3} $$
= 0.3333
= 33.33%
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