The sum of two numbers is 59 and their product is 840. Find the sum of their squares.

Let the two numbers are $$a$$ and $$b$$

Given,

Product of the numbers = 840

$$=$$>  $$ab = 840$$

Sum of the numbers = 59

$$=$$>  $$a+b = 59$$

$$=$$>  $$\left(a+b\right)^2=59^2$$

$$=$$>  $$a^2+b^2+2ab=3481$$

$$=$$>  $$a^2+b^2+2\left(840\right)=3481$$

$$=$$>  $$a^2+b^2+1680=3481$$

$$=$$>  $$a^2+b^2=3481-1680$$

$$=$$>  $$a^2+b^2=1801$$

$$\therefore\ $$Sum of their squares = 1801

Hence, the correct answer is Option B