Question 79

How many kg of pure salt must be added to 30 kg of a 2% solution of salt and water to increase it to a 10% solution?

Solution

Amount of salt in 30kg solution = $$\frac{2 \times 30} {100}$$ = 0.6 kg

Let x kg of pure salt is added:

Then, $$\frac{0.6 + x} {30 + x}$$ = $$\frac{10} {100}$$

60 + 100x = 300 + 10x

100x - 10x = 300 - 60

90x = 240

x = $$\frac{240} {90}$$

x = $$\frac{8} {3}$$

x = 2$$\frac{2} {3}$$ kg

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