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Solution
$$ab(a - b) + bc(b - c) + ca(c - a)$$
Let the a = 2, b = 1, c = 0.
= $$2(2 - 1) + 1 \times 0Â (1 - 0) + 0 \times 2(0 - 2)$$
= 2
From option D,
$$(b - a)(b - c)(c - a)$$
Put the a = 2, b = 1, c = 0.
= $$(1 - 2)(1 - 0)(0 - 2)$$
= -1 $$\times 1 \times -2$$
= 2
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