Question 93

Anita performs a particular chase at the speed of speed (9/10) at regular speed, which he takes 25 minutes longer than usual time. Find the time you usually take. (In minutes)

Solution

Let usual speed = $$10$$ m/min and usual time taken = $$t$$ min

=> New speed = $$9$$ m/min and new time = $$(t+25)$$ min

Also, speed is inversely proportional to time.

=> $$\frac{10}{9}=\frac{t+25}{t}$$

=> $$10t=9t+225$$

=> $$10t-9t=t=225$$

$$\therefore$$ Usual time taken = 225 minutes

=> Ans - (A)

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