a man left x for y.another man left y for x at the same time.after reaching their destinations,they turned back without stopping.they crossed each other at a point 30km for x on their onward trip and 20 km from y on their return trip.find xy(in km)

Hi Ayush Pawar,
Let the distance between X and Y be 'D' and A travels from X to Y and B travels from Y to X.
Before meeting for the first time, A covers 30 km and B covers D - 30 km
Before meeting for the second time, A covers D + 20 and B covers 2D - 20
Time is constant in both cases. Let the speeds of A and B be 'a' and 'b'
30/a = D-30/b .......... (1)
D+20/a = 2D-20/b ........... (2)
30/D+20 = D-30/2D-20
Solving we get, D = 70km
Hope this helps!