Edit MetaData
7 years, 7 months ago
just to verify whether the below method is a fluke or correct in approach:
even factors of 135000 and 108000 would not vary for powers of 2 and 3 as in both the cases for 135000, 2 and 3 powers are less or equal to that of for 108000. only 5 will make the difference. For 135000 power of 5 can take values 0,1,2,3 and 4 but for 108000 power of 5 can take values 0,1 and 2 only.
So total number of factors = 3*4*2 = 24
3 => 1,2,3 powers of 2
4=> 0,1,2,3 powers of 3
2 => 3,4 powers of 5
7 years, 7 months ago
I guess ur approach is correct and simple. No, it's not a fluke
Quick, Easy and Effective Revision
By proceeding you agree to create your account
Free CAT Formulae PDF will be sent to your email address soon !!!