Question 1

ABCD is a cyclic trapezium with AB || DC and AB = diameter of the circle. If angleCAB = $$30^{\circ}$$, then angleADC is

Solution

let angle CDA = x 

since AB is parallel to CD, angle ACD=30 and angle CAD=30 

in triangle ACD, 

sum of all three angles = 180

30 + 30 + x = 180

x = 120

so the answer is option B.


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