ABCD is a cyclic trapezium with AB || DC and AB = diameter of the circle. If angleCAB = $$30^{\circ}$$, then angleADC is
let angle CDA = xÂ
since AB is parallel to CD, angle ACD=30 and angle CAD=30Â
in triangle ACD,Â
sum of all three angles = 180
30 + 30 + x = 180
x = 120
so the answer is option B.
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