All sides of a quadrilateral ABCD touch a circle. If AB = 6 cm. BC = 7.5 cm. CD = 3 cm, then DA is
Given : AB = 6 cm. BC = 7.5 cm. CD = 3 cm
To find : DA = ?
Solution : Tangents from the same point to a circle are equal in length.
=> $$AE=AH$$, $$BE=BF$$, $$CG=CF$$ and $$DG=DH$$
Adding above equations, we get :
=> $$(AE+BE)+(CG+DG)=(BF+CF)+(AH+DH)$$
=> $$AB+CD=BC+DA$$
=> $$6+3=7.5+DA$$
=> $$DA=9-7.5=1.5$$ cm
=> Ans - (D)
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