SSC CHSL 17 March 2018 Morning Shift

Question 2

If a number 657423547X46 is divisible by 11, then find the value of X.

Solution

For a number $$657423547X46$$ to be divisible by 11, the difference between the sum of numbers at even position and odd position should be either '0' or '11'.

Sum of digits at odd position (starting from right) = $$6+X+4+3+4+5=(22+X)$$

Even positions = $$4+7+5+2+7+6=31$$

=> $$22+X-31=0$$

=> $$X=9$$

=> Ans - (B)

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