Question 3

How many solutions does a pair of linear equations will have, if the equations are 4x+5y-6=0 and 16x+20y+20=0?

Solution

Equations : $$4x+5y-6=0$$ and $$16x+20y+20=0$$

The ratio of coefficients is = $$\frac{4}{16}$$ $$,\frac{5}{20}$$ $$,\frac{-6}{20}$$

=> $$\frac{1}{4}=\frac{1}{4}\neq\frac{-3}{10}$$

$$\because\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}$$, thus the equations have no solutions.

=> Ans - (A)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: