Solution
Given : $$(8,2)$$ is the solution of equation : $$x+4y-2k=0$$
=> $$8+4(2)-2k=0$$
=> $$2k=8+8=16$$
=> $$k=\frac{16}{2}=8$$
$$\therefore$$ $$k^2=(8)^2=64$$
=> Ans - (C)
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