Equation : $$7x+12y=16$$
Solving the equation by putting $$x=0$$, => $$12y=16$$
=> $$y=\frac{16}{12}=\frac{4}{3}$$
Also, putting $$y=0$$, => $$7x=16$$
=> $$x=\frac{16}{7}$$
$$\therefore$$ Plotting the graph for points $$(0,\frac{4}{3})$$ and $$(\frac{16}{7},0)$$
Thus, the equation $$7x+12y=16$$ passes through I, II and IV quadrants.
=> Ans - (D)
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